A chemist wants to make 5.5 L of a 0.250 M CaCl2 solution, find the mass

asked Mar 5, 2019 233k views

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5 votes

0.250 M = mol/5.5 L
mol = (0.250)(5.5) = 1.375 mol CaCl2

MW CaCl2 = 40 + 2*35.5 = 111 g/mol

m CaCl2 = 1.375 * 111 = 152.625 g

Daniel Castro answered Mar 11, 2019

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