Question

PLEASE HELP! 30 POINTS! What are the zeros of the function?

f(t)=t^2-13t+36

Enter your answers in the boxes.

Answer 1

Solve the equation

`f(t) = 0`
So we have:

`{t}^(2) - 13t + 36`
Factor, 2 numbers of which the sum is -13 and multiplying gives 36, these two are -4 and -9
So solve:

`(x - 4)(x - 9) = 0`
The solutions:
4 and 9