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Fitness center currently has 320 members. Monthly membership fees are $45. The manager of the fitness center has determined that each time the membership fees increase by $5, approximately 10 members leave and go to a different gym.

Write an equation that can be used to find the revenue of the fitness center in dollars, y, after x price increases of $5.

y = -50x2 + 1,150x + 14,400

y = -50x2 + 3,425x + 14,400

y = -50x2 + 2,975x + 14,400

y = -50x2 + 2,050x + 14,400

asked
User Jogy
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7.8k points

2 Answers

6 votes

y = -50x2 + 1,150x + 14,400 - This one seems to be the closest to the answer

answered
User Hakan
by
8.4k points
4 votes

Answer:

y= -50x^2+1,150x+14,400

Explanation:

fitness center currently has 320 members. Monthly membership fees are $45. The manager of the fitness center has determined that each time the membership fees increase by $5, approximately 10 members leave and go to a different gym.

LEt x be the number of price increases of $5

y is the revenue

Revenue= membership fee * members

for x number of increase in fee by 5 then member ship fee becomes 45+5x

approximately 10 members leave, so members becomes (320-10x)

y = (45+5x) (320-10x)

Multiply it using FOIL method

y=45 * 320 +45*(-10x) + 5x * 320 + 5x * (-10x)

y=14400 - 450x + 1600x - 50x^2

Combine like terms

y= -50x^2+1150x+14400

answered
User Welch
by
8.1k points

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