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How many moles of gas sample are 5.0 L container at 373K and 203kPa

1 Answer

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For the purpose we will here use the ideal gas law:

p×V=n×R×T

V=
5.0 L

T=
373K

p=
203kPa

R is
universal gas constant, and its value is 8.314 J/mol×K

Now when we have all necessary date we can calculate the number of moles:

n=p×V/R×T

n= 203 x 5 / 8.314 x 373 = 0.33 mole
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User Wei Li
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