Question

Suppose the ages of cars driven by employees at a company are normally distributed with a mean of 8 years and a standard deviation of 3.2 years. What is the z score of a car that is 6 years old?

Answer 1

z=(6-8)/3.2=(-2)/3.2=-0.625

Explanation:

z=(6-8)/3.2=(-2)/3.2=-0.625

Answer 2

Z-scores are given by the formula
`z=(x-\mu)/\sigma`, where x is the data point you're using, μ is the mean and σ is the standard deviation. Using our information we have
z=(6-8)÷3.2=(-2)÷3.2=-0.625.