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5). What was the value of 1/2^-2 x^-3 y^5 for x=2 & y= -4

A) 16

B) -4

C) -1/32

D) -16

asked
User Jobima
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1 Answer

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The value of the expression is given by:
(1/2)^-2x^-3y^5
substituting x=-4 and y=2 we get:
(1/2)^-2(-4)^-3(2)^5
=2^5/((1/2)²×(-4)³)
=-2
answered
User Dave Sibiski
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