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The nurse is reviewing the electrocardiogram of a client who has elevated st segments visible in leads ii, iii, and avf. which is the nurse's best action?

2 Answers

3 votes

Answer:

Nurse must provide necessary medication such as

Aspirin, streptokinase, heparin and an ACE inhibitor

Step-by-step explanation:

When the ST segment is elevated in the inferior leads i.e II, III and aVF, then this condition signifies that the RCA (right coronary artery) is injured or occluded and inferior myocardial tissue faces acute infraction. This can cause several complications and in severe cases can prove to be fatal. It is a sign of heart attack. Thus, the nurse must provide necessary medication such as

Aspirin, streptokinase, heparin and an ACE inhibitor

answered
User Rosghub
by
7.7k points
3 votes
The nurse should call the attention of the attending physician or the healthcare practitioner in charge. ST segment elevation in leads II, III, and aVF signify a massive transmural inferior wall infarct that can lead to loss of ventricular function and parasympathetic stimulation of the heart causing bradyarrhythmias then into cardiogenic shock and eventually death of the patient. 
answered
User Ruhulrahat
by
8.4k points
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