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The area of a rectangle is 20x^2-27x-8.the length is 4x+1. What is the width?

The area of a rectangle is 20x^2-27x-8.the length is 4x+1. What is the width?
asked 102k views
2 votes
The area of a rectangle is 20x^2-27x-8.the length is 4x+1. What is the width?

asked
User PattimusPrime
by
8.9k points

2 Answers

5 votes
⇒w=(5x−8)
Step-by-step explanation:
Let width be w
Then w(4x+1)=20x2−27x−8
So
(?x+?)(4x+1)=20x2−27x−8
Note that
5×4=20 and (−8)×(+1)=−8
⇒w(4x+1)
=(5x-8)(4x+1)=20x2+5x−32x−8
⇒w(5x−8)
answered
User GrafikRobot
by
8.8k points
3 votes
w= (5x - 8) this is your answer
answered
User Mtheriault
by
8.6k points
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