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Solve. 2m^2-7m-13=-10

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2m^2-7m-13=-10\ \ \ |+10\\\\2m^2-7m-3=0



a=2;\ b=-7;\ c=-3\\\\b^2-4ac=(-7)^2-4\cdot2\cdot(-3)=49+24=73\\\\m_1=(-b-√(b^2-4ac))/(2a);\ m_2=(-b+√(b^2-4ac))/(2a)\\\\m_1=(-(-7)-√(73))/(2\cdot2)=(7-√(73))/(4)\\\\m_2=(-(-7)+√(73))/(2\cdot2)=(7+√(73))/(4)

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