Question

Evaluate g(n-5) if g(x)=x^2-6/2x

Answer 1

g(x) = (x^2-6) / 2x

g( n-5) = ( [n-5]^2 -6) / 2(n-5)

= ( n^2 -10n +25 -6 ) / 2(n-5) or ( n^2 -10n +25 -6 ) / (2n-10)
Your Answer

I did foil first and got n^2-10n+25
then did 25-6 to get 19.
so n^2-10n+25 is on top.////// should have been n^2 -10n +19
and the bottom is 2(n-5) so I distributed the 2 and got 2n-10

so n^2-10n+25
2n-10
= (n^2 -10n +19) / 2(n-5)

Answer 2

Answer: We want to evaluate g(x) in x = n -5, where g(x) = (x^2-6)/2x

then, doing it step by step:
`g( n- 5)= ((n-5)^(2) - 6 )/(2*(n-5))= ((n^(2) - 2*5*n + 25) - 6 )/(2n - 10) = (n^(2) - 10n + 19 )/(2n - 10)`

where i used that (a - b)^2 = a^2 -2ab + b^2

So the correct option is C.