Cody graphed a quadratic equations, y = -(x+3)^2 + 1. What were cody's mistakes?

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asked Feb 16, 2019 223k views

2 Answers

Asdrubal · Answer 1 · 2019-02-20T20:03:37+0000

We can see in the graph attached below how the real curve would look.

The vertex of cody's graph was ploted in x = 3, where it should be x = -3

This changes the position of the parabola

Cody graphed a quadratic equations, y = -(x+3)^2 + 1. What were cody's mistakes?-example-1

Cody graphed a quadratic equations, y = -(x+3)^2 + 1. What were cody's mistakes?

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