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TanA+tanB=sin(A+B)/cosAcosB

TanA+tanB=sin(A+B)/cosAcosB
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TanA+tanB=sin(A+B)/cosAcosB

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User DorianFM
by
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1 Answer

5 votes
Do you need to prove that it is equal?
If so:

SinA/cosA + sinB/cosB = (sinAcosB + sinBcosA)/cosAcosB

(SinAcosB + sinBcosA)/cosAcosB = (SinAcosB + sinBcosA)/cosAcosB

answered
User Ganesh M
by
8.3k points
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