Question

How do you find the value of x in degrees.

sin 2x - 1 = 0

Answer 1

`\bf sin(2x)-1=0\implies sin(2x)=1\implies sin^(-1)[sin(2x)]=sin^(-1)(1) \\\\\\ 2x=sin^(-1)(1)\implies 2x=\cfrac{\pi }{2}\implies x=\cfrac{\pi }{4}\textit{ which is }45^o`