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The longest side of an acute isosceles triangle is 8 centimeters. rounded to the nearest tenth, what is the smallest possible length of one of the two congruent sides?

A:4.0
B:4.1
C:5.6
D:5.7

2 Answers

3 votes
4.1cm
I helped you so you're welcome
answered
User Qwattash
by
8.2k points
4 votes
It is an acute isosceles triangle, so the vertex angle is smaller than 90.
if the vertex angle is 90, then it is a 45-45-90 triangle, when the longest side (the hypotenuse) is 8, each leg is 8/√2=5.65685

Because the vertex angle needs to be smaller than 90, the two equal side is larger than 5.6568, I'd go with D.
answered
User Jonathan Kuhn
by
8.2k points

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