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How many grams of ammonia would be formed from the complete reaction of 4.50 moles hydrogen

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Answer:

51 grams of ammonia would be formed.

Step-by-step explanation:


3H_2+N_2\rightarrow 2NH_3

Moles of hydrogen gas = 4.50 moles

According to reaction, 3 moles of hydrogen gas gives 2 moles of ammonia gas.

Then 4.50 moles of hydrogen gas will give:


(2)/(3)* 4.50 mol=3.00 molof ammonia

Mass of 3.00 moles of ammonia:


17 g/mol* mol=51 g

51 grams of ammonia would be formed.

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