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A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.

A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.
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A company has a cost equation of c=0.925x^2-4x+20 and a profit equation of p=-1.125x^2+6x+40. Solve for the breakeven point.

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User Tasos Vogiatzoglou
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8.3k points

1 Answer

3 votes
0.925x^2 - 4x + 20 = -1.125x^2 + 6x + 40 (at break even point)

2.05x^2 - 10x - 20 = 0

x = [ - (-10) +/- sqrt(100 - 4*2.05*-20) / (2*2.05)

x = 6.40, -1.52 Ignore the negative

Answer is 6.40


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User David Torres
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