Question

A 63 kg gymnast climbs 15 m up a vertically hanging rope. He completed the distance in 70 seconds. How much power did his body output to achieve the climb?

Answer 1

Answer:b

Step-by-step explanation:

hope it helps

Answer 2

The work required is equal to the potential energy when he's at the top. This is given by


`E=mgh=63kg * 9.8 (m)/(s^2) * 15m=9261J`

The power is this energy divided by the time it took to do the work


`P= (E)/(t)= (9261J)/(70s) =132.3W`