Question

as a 15.1-gram sample of a metal absorbs 48.75 j of heat its temperature increases 25.0 k what is the specific heat capacity of the metal

Answer 1

Specific heat capacity (c) of a material is related to the Energy Absorbed (Q), mass of the material (m) and the change in temperature (T) by the following equation:


`c= (Q)/(mT)`

Substituting the values of Q, m and T in the above equation, we get:


`c= (48.75)/(15.1*25)=0.129`

So the specific heat capacity of the metal with given conditions will be 0.129 J/g.K