Question

The earth has a radius of 6380 km and turns around once on its axis in 24 h. (a) what is the radial acceleration of an object at the earth's equator? give your answer in m/s and as a fraction of g

Answer 1

we know that

a = ω²r
r = 6380 km----------- > 6.38e6 m
ω=2π/86400 sec
a=(2π/86400) ² (6.38e6 m )------------ > 0.03374

a = 0.03374 m/sec²

if g------------------- > 9.8 m/sec²
X----------------------> 0.03374 m/sec²
X=0.03374 /9.8---------- > 0.00344
a = 0.00343 g

the answer is
a = 0.03374 m/sec²
a = 0.00343 g