Question

How do I solve this for x?

Answer 1

Factor.

Think of it has a normal quadratic equation with an x squared term, x term, and constant.


`(x^2+7)(x^2-4)=0`


`x^2+7=0`


`x^2=-7`


`x= √(-7)`

That won't give use any real roots.


`x^2-4=0`


`x^2=4`


`x=-2,2`

So x = -2 and x = 2