Question

Find an equation in standard form for the hyperbola with vertices at (0, ą2) and foci at (0, ą7).

y squared over forty nine minus x squared over four = 1

y squared over forty five minus x squared over four = 1

y squared over four minus x squared over forty nine = 1

y squared over four minus x squared over forty five = 1

Answer 1

Answer:D

Explanation:

Answer 2

The answer is D) y^2/4 - x^2/45 =1