Question

Line EF passes through the points (0, 1) and (3,3). Line JK passes through the points (8, 2) and (6, 5). These lines are

Answer 1

EF ( x1=0, y1=1), (x2=3, y2=3)
JK (x1=8, y1=2), (x2=6, y2=5)

Slope of a line=(y2-y1)/(x2-x1)

Slope of EF =( 3-1)/(3-0)= 2/3
Slope of JK =(5-2)/(6-8)= 3/-2

Since the slopes of those lines are negative reciprocal the lines are perpendicular

Line EF is perpendicular to JK