Answer:
No it is still 11 feet from the water at 2 seconds
2.1651 seconds is when it will hit the water
Explanation:
h(t) = -16 t^2 +75
This is the formula for the distance
The -16t^2 is due to gravity and the 75 is the height above the bridge
We want to know the height a t =2
h(2) = -16 (2)^2 +75
h(2) =-64 +75
h(2) = 11
The rock will be 11 ft above the water
When will the rock hit the water
h = 0
0 = -16 t^2 +75
Subtract 75 from each side
-75 = -16t^2 +75-75
-75 = -16t^2
Divide by -16
-75/-16 = -16t^2 /-16
75/16 = t^2
Take the square root of each side. We only take the positive square root since time must be positive
sqrt(75/16) =t
5/4 sqrt(3) = t
2.1651 seconds = t