Question

A rectangle has a perimeter of 82 inches. The width of the rectangle is 15 inches more than the length. What is the width, in inches, of the rectangle?

Answer 1

Explanation:

`perimeter = 82 \: inches \\ perimeter = 2l \: + 2w \\ = 2l + 2(15 + l) \\ 82 = 2l + 30 + 2l \\ 82 - 30 = 4l \\ 52 = 4l \\ (52)/(4) = (4l)/(4) \\ l = 13 \\ w = 23 \\ \\ check \\ perimeter \: = 2l + 2w \\ = 2(13) + 2(28) \\ = 26 + 56 \\ = 82`