Question

Toluene, c6h5ch3, is a liquid compound similar to benzene, c6h6. it is the starting material for other substances, including trinitrotoluene (tnt). find the molality of toluene in a solution that contains 35.6 g of toluene and 125 g of benzene.

Answer 1

3.08 m

Step-by-step explanation:

To calculate the molarity, you have to use the following formula:

`(moles of solute)/(kg  of solvent)`

From the question, we already have the mass of the solvent (benzene); However, for the calculation of molality, we require the solvent in Kg, therefore we do the conversion from g to kg:

125 g of benzene = 0.125 kg of benzene.

To obtain the number of moles of solute we have to use the molecular weight of toluene, which is 92.14

To convert from g to moles, we divide the grams of toluene by the molecular weight:

`(35.6g)/(92.14gmol^(-1) )`

Therefore, we have 0.386 moles of toluene.

The last step will be to replace all the values in the molality formula:

`(0.386 moles of toluene)/(0.125 kg of benzene)` = 3.08 m

I hope this clarifies your inquiry.

Answer 2

Toulene = 35.6 g
Benzene = 125 g = 0.125 kg
Molecular weight of Toluene C6H5CH3 = 92.1g/mol
Moles of toulene = 35.6 g / 92.1 g/mol = 0.3865 mol

Now the molarity of the toulene in the given solution = 0.3865 / 0.125 = 3.092 m
Molarity of C6H5CH3 = 3.092 m