Question

What is the equation of a line with a slope of 7 and a point (1, 8) on the line?

Express the equation in the form of y = mx + b, where m is the slope and b is the y-intercept.


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Answer 1

ANSWER

The required equation is


`y = 7 x+ 1`

Step-by-step explanation

Let the equation of the line be


`y = mx + b...(1)`
where

`m = 7`
is the slope of the line. We substitute this value of the slope into the equation (1) to obtain,



`y = 7x + b...(2)`


Since the point (1,8) lies on the line, it must satisfy this equation.



We substitute the x and y value of the point into the equation(2) to get,


`8 = 7(1) + b`

This simplifies to give us,


`8=7+b`


We solve for b to get,


`b = 8 - 7`


`b = 1`


We substitute the value of b back into equation (2) to get



`y = 7x + 1`