asked 91.7k views
4 votes
In 2006, the population of Tewksbury, Rhode Island was 25,000, and it was growing at an annual rate of 2.2%. What is the growth factor for the town?

2 Answers

1 vote

Answer:

The growth factor is 1.022

Explanation:

Exponential growth is modeled by the equation

y= a b^x

where a is the initial amount and b is 1 + the growth percent and x is the time in years

b = 1+.022 = 1.022

1 vote
It is 200% that is wat i got

answered
User BalusC
by
7.8k points
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