asked 34.2k views
4 votes
HELP FAST PLEASE!!!!!

Sandra wants to evaluate 2cot(-9pi/2). Herwork is shown below. What did she do wrong?
2cot(-9pi/2)=2cot(9pi/2)
2cot(-9pi/2)=2cot(pi/2)
2cot(-9pi/2)=2(0)
2cot(-9pi/2)=0

1 Answer

4 votes

Alright, lets get started.

The answer Sandra got is correct that is zero but there are some mistakes she made while writing steps.


2 cot((-9\pi)/(2)) = 2 cot((9\pi)/(2)) Incorrect step

Because as per even/odd identity,

Cot (-Θ) = - cot (Θ)

Hence


2 cot ((-9\pi)/(2)) = - 2 cot ((9\pi)/(2))

Now,

It could be written as


-2 cot ((9\pi)/(2)) = -2 cot ((\pi)/(2))



-2 * 0

0

Hence the answer is 0. : Answer

Hope it will help :)

answered
User Mister Nobody
by
7.9k points
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