Question

Using the graph of f(x) = log2x below, approximate the value of y in the equation 22y = 6.

log base 2 graph

Answer 1

f(x) = log2x- -------> y=log2x-------- > 2^(y)=x (I)

therefore

in the equation 2^(2y) = 6---- >(2^(y))^2 = 6 (II)

(I) in (II)

((x))^2 = 6-----------------x=2.45

using a graphic tool
see graphic attached

for x=2.45 the value of y approximate is 1.2928