Question

Multiply. −3/7xy(−35x^3y^2)

This is REALLY IMPORTANT I NEED IT DONE BY 2/4/2018 1:00
THANK YOU (SHOW YOUR WORK OR NO POINTS)

Answer 1

-3/7xy(-35x^3y^2)

-3/7 * -35 = 105/7 = 15
x * x^3 = x^4
y * y^2 = y^3

so u r left with : 15x^4y^3 <==

Answer 2

Here the multiplication of the expression given,

`-(3)/(7)xy(-35x^3y^2)`

To multiply the expression first we have to multiply the signs negative and negative. We know that negative times negative will give positive.

`(-)(-)(3)/(7)xy(35x^3y^2)` =
`+(3)/(7)xy(35x^3y^2)`

Now we will multiply the numbers
`(3)/(7)` and 35.

`((3)/(7) )(35) xy(x^3y^2)`

=
`((3)(35))/(7)xy(x^3y^2)`

=
`(105)/(7) xy(x^3y^2)`

=
`15xy(x^3y^2)`

Now we will multiply x with x and y with y. We will use properties of exponent. We know that when base is same, we have to add the exponents only. If we have
`(x^m)(x^n) = x^((m+n))`.

So here x means
`x^1`.

Multiplying we will get here,

`15xy(x^3y^2) = 15x^1y^1(x^3y^2)`

=
`15x^((1+3))y^((1+2))`

=
`15x^4y^3`

We have got the required answer here.