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Factor completely. 49 t6 - 4 k8

asked
User Sarita
by
8.6k points

1 Answer

3 votes
49 t^6 - 4 k^8
= (7t^3)^2 - (2k^4)^2
= (7t^3 + 2k^4)(7t^3 - 2k^4)
answered
User Lakshmaji
by
8.6k points
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