The length of the base of a square pyramid is 9 inches the slant height is 12 inches what is the surface area of the pyramid

Question

asked Dec 8, 2019 78.5k views

1 Answer

Bhusak · Answer 1 · 2019-12-12T19:41:14+0000

Answer:

The surface area is
$297\ in^(2)$

Explanation:

we know that

The surface area of the square pyramid is equal to the area of the square base plus the area of its four lateral triangular faces

so

SA=b^(2)+4[(1)/(2)(b)(l)]

where

$b=9\ in$

$l=12\ in$ -----> the slant height

substitute the values

SA=9^(2)+4[(1)/(2)(9)(12)]

$SA=297\ in^(2)$