Question

How many milliliters of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl? 250.0 milliliters 100.0 milliliters 62.5 milliliters 0.1 milliliters

Answer 1

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Answer 2

100.0 milliliters

Step-by-step explanation:

Using the dilution formula,

M₁V₁ = M₂V₂

Where M₁ and M₂ are the initial and final molarity, V₁ and V₂ are the initial and final volume.

V₁ = 250 ml

M₁ = 1.2 M

M₂ = 3M

Plugging in the numbers in the dilution formula we get,

1.2 M x 250 ml = 3M x V₂

V₂ =
`(1.2 M x 250 ml)/(3M)` = 100 ml

Therefore, 100 ml of a 3.0 M HCl solution are required to make 250.0 milliliters of 1.2 M HCl.