What is the value of 81x2y3+z if x=3 y=4 and z=19

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asked Feb 9, 2019 125k views

1 Answer

Deacon · Answer 1 · 2019-02-14T15:56:56+0000

Ok first of all I am assuming you mean

81.(x**2).(y**3) +z = Value

We just need to simply substitute x , y and z

81.(3*3)(4*4*4) +19 = Value

46656 + 19 = Value..............>> Value = 46675

What is the value of 81x2y3+z if x=3 y=4 and z=19

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