Question

Given △ABC, sin(A) =

A. cos(B)
B. sin(B)
C. cos(C)
D. tan (C)

Answer 1

the answer is cos(C).

Answer 2

we know that

In a right triangle ABC

m∠A+m∠C=
`90\°` -------> by complementary angles

so

`sin(A)=cos (C)\\and\\cos(A)=sin (C)`

therefore

the answer is the option

C. cos(C)