To choose the graph, we must make sure that it satisfies both equations of the system simultaneously.
 We have then:
 a line includes points 0 comma 4 and 3 comma 5
 Verifying:
 (0, 4)
 (0) - 3 (4) = -12
 0-12 = -12
 -12 = -12
 (3, 5)
 2x - y = 1
 2 (3) - (5) = 1
 6-5 = 1
 1 = 1
 answer 
 The graph that matches the system of equations is
 a line includes points 0 comma 4 and 3 comma 5