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Five identical rectangles are arranged to form a larger rectangle $pqrs$, as shown. the area of $pqrs$ is $4000$. what is the length, $x$, rounded off to the nearest integer?
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Five identical rectangles are arranged to form a larger rectangle $pqrs$, as shown. the area of $pqrs$ is $4000$. what is the length, $x$, rounded off to the nearest integer?
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Feb 20, 2019
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Five identical rectangles are arranged to form a larger rectangle $pqrs$, as shown. the area of $pqrs$ is $4000$. what is the length, $x$, rounded off to the nearest integer?
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Brett Stottlemyer
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Let x be length and y be width
from figure
2x = 3y ...(1)
area = (x+y)(2x) ...(2)
from equation 1 we get
y=2x/3
putting this value in equation 2
(x+2/3x)(2x)= area
now given area=4000
(x+2/3x)(2x)= 4000
solving
x^2 (10/3) = 4000
x^2 = 1200
x=1200^(1/2)
x=34.64
x=35cm
SpacyRicochet
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Feb 26, 2019
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SpacyRicochet
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