asked 100k views
3 votes
A student performed the following steps to find the solution to the equation x^2+14x+48=0 . Where did the student go wrong?

Step 1. Factor the polynomial into (x + 8) and (x - 6)
Step 2. x + 8 = 0 and x - 6 = 0
Step 3. x = -8 and x = 6

A. The student did not make any mistakes, the solution is correct
B. in Step 3
C. in Step 1
D. in Step 2

asked
User Gabuchan
by
8.0k points

2 Answers

1 vote
In step 1
It should be (x+8)(x+6)
answered
User Felene
by
7.5k points
4 votes

Answer:

In step 1 the student go wrong.

Explanation:

Given that a student performed the following steps to find the solution to the equation


x^2+14x+48=0

we have to tell where the student wrong.


x^2+14x+48=0

Step 1: Factor the polynomial


x^2+14x+48


x^2+6x+8x+48


x(x+6)+8(x+6)


(x+6)(x+8)

Hence, (x+6) and (x+8) are the factors of given polynomial.

In step 1, the student takes the factor (x + 8) and (x - 6)

Hence, In step 1 the student go wrong.

Option C is correct

answered
User Webnesto
by
8.1k points

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