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Janet wants to find the spring constant of a given spring, so she hangs the spring vertically and attaches a 0.50 kg mass to the spring's other end. if the spring stretches 3.0 cm from its equilibrium position, what is the spring constant?

1 Answer

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Given: Mass m = 0.50 Kg; Force = Weight = mg F = (0.50 Kg)(9.8 m/s²)

F = 4.9 N

Displacement x = 3.0 cm convert to meter x = 0.03 m

Required: Spring constant k = "

Formula: F = kx

k = F/x

k = 4.9 N/0.03 m

k = 163.33 N/m




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User Wololo
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