Question

An acorn with a mass of 0.0300 kilograms falls from a tree. What is its kinetic energy when it reaches a velocity of 5.00 m/s? 1.47 J .075 J 0.375 J cannot be determined without knowing how far the acorn has fallen

Answer 1

KE = 1/2 m v^2.

That's 0.375 J.

Answer 2

Kinetic energy of acorn is 0.375 J .

Explanation:

Formula

Kinetic energy is defined by

`K.E = (1)/(2)mv^(2)`

Where m is mass and v is velocity .

As given

An acorn with a mass of 0.0300 kilograms falls from a tree with a velocity of 5.00 m/s .

m = 0.0300 Kg

v = 5 m/s

Putting all the values in the formula

`K.E = (1)/(2)* 0.0300* 5* 5`

`K.E = (1* 0.0300* 5* 5)/(2)`

`K.E = (0.75)/(2)`

K.E = 0.375 J

Therefore the kinetic energy of acorn is 0.375 J .