Question

What is the point-slope form of a line that has a slope of 5 and passes through the point (3, –4)?

y – 3 = 5[x – (–4)]
–4 – y1 = 5(3 – x1)
y – (–4) = 3(x – 5)
y – (–4) = 5(x – 3)

Answer 1

y – (–4) = 5(x – 3)

Explanation:

Answer 2

The generic form for this case is given by
y = m (x-xo) + yo
where
xo: x coordinate
me: y coordinate
Substituting the values we have
y = 5 (x-3) - 4
Therefore, the answer in this case is
y – (–4) = 5(x – 3)