asked 164k views
3 votes
The angle of elevation to the top of a 20-story skyscraper is measured to be 2 degrees from a point on the ground 5,280 feet from the building. What is the height of the skyscraper to the nearest hundredth foot?

asked
User Kingdaro
by
8.2k points

2 Answers

5 votes
Height of the skyscraper to the nearest hundredth foot
= 5280 Tan(2)
= 184.38
answered
User IDroid
by
8.6k points
1 vote

Answer:


184.38\ ft

Explanation:

we know that

In a right triangle the tangent function of an angle
\theta is equal to divide the opposite side to the angle
\theta by the adjacent side to the angle
\theta

In this problem we have


\theta=2\°


adjacent\ side=5,280\ ft

Let

h-----> the opposite side to the angle
\theta (represent the height)

so


tan(2\°)=h/5,280


h=5,280*tan(2\°)=184.38\ ft

see the attached figure to better understand the problem

The angle of elevation to the top of a 20-story skyscraper is measured to be 2 degrees-example-1
answered
User RunarM
by
8.2k points
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