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A compound contains 75% carbon and 25% hydrogen by mass. What is the empirical formula for this compound?

asked
User Miojamo
by
8.3k points

2 Answers

1 vote

Answer:

CH4

next answer is Na3PO4

Step-by-step explanation:

answered
User MoxieandMore
by
8.3k points
5 votes
Answer:

CH4

Step-by-step explanation:

For this kind of problem, you can assume that the weight of the unknown sample is 100g ( since 75% C + 25% H = 100%).

Thus,

weight of C = 75g
weight of H = 25g

Since chemical formulas deal with number of moles rather than weight in grams, you need to convert each element by multiplying it to their respective atomic masses.

atomic mass of C=12.01gmol

atomic mass of H=1.01gmol

Thus,

mol C = 75 grams x 1 mol12.01grams = 6.245 mol C

mol H = 25 grams x 1 mol1.01grams = 24.752 mol H

Now we can see from the computation above that every

6.245 mol C = 24.752 mol H

Dividing both sides by the smallest number of moles, (in this case 6.245 mol C)

C = 6.245mol6.245mol = 1
H = 24.752mol6.245mol = 3.98 ≈ 4

Therefore, empirical formula is C1H4 or simply, CH4.

answered
User Munsterlander
by
7.9k points

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