What is the volume occupied by 3.00 × 1023 molecules of bromine gas at STP? a 404.5 L B. 0.80 L C. 2.2 × 10-2 D. 11.2 L

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Ellin · Answer 1 · 2019-11-02T02:41:36+0000

D. 11.2 L , since we are at STP we will use the ideal gas law. 3.0 x 10²³ 6.02x10²³ / 1 mole and if you continue with this process it will give you 11 L.

What is the volume occupied by 3.00 × 1023 molecules of bromine gas at STP? a 404.5 L B. 0.80 L C. 2.2 × 10-2 D. 11.2 L

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