(x-5)^2 =17 rounded to the nearest tenth

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asked Nov 23, 2019 133k views

2 Answers

Matt Refghi · Answer 1 · 2019-11-28T20:36:43+0000

(x - 5)² = 17

root both of sides
√(x-5)² = √17
x - 5 = √17

move the five to the right
x - 5 = √17
x = 5 + √17
x = 5 + 4.1
x = 9.1

The solution is x = 9.1

(x-5)^2 =17 rounded to the nearest tenth

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