Question

Evaluate 8a+3b-10+c^28a+3b−10+c ​2 ​​ 8, a, plus, 3, b, minus, 10, plus, c, start superscript, 2, end superscript when a=2a=2a, equals, 2, b=5b=5b, equals, 5, and c=4c=4c, equals, 4.

Answer 1

The given expression
`8a+3b-10+c^2` at a = 2 , b = 5 and c = 4 is 37.

Explanation:

Given : expression
`8a+3b-10+c^2`

We have to evaluate the given expression
`8a+3b-10+c^2` at a = 2 , b = 5 and c = 4

Consider the given expression
`8a+3b-10+c^2`

Substitute, a = 2 , b= 5 and c = 4

We have,

`=8(2)+3(5)-10+(4)^2`

Simplify, we have,

`=16+13-10+16`

We get,

= 37

So, The given expression
`a+3b-10+c^2` at a = 2 , b = 5 and c = 4 is 37.