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How does the volume of a cylinder change when it’s diameter is doubled

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User Logee
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recallin that, the diameter is twice as long as the radius, namely the radius is half the diameter, so, if the diameter is doubled, the radius is also doubled.


\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h\quad \begin{cases} r=radius\\ h=height\\ -----\\ r=\stackrel{doubled}{2r} \end{cases}\implies V=\pi (2r)^2 h \\\\\\ V=\pi (2^2r^2)h\implies V=\pi 4r^2 h\implies V=4~(\pi r^2 h)

notice, the new volume is 4 times (πr² h), namely 4 times the original.
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User DMI
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