Lesson 10: Congruent Triangles ._.

Question

asked Mar 4, 2019 199k views

2 Answers

Saera · Answer 1 · 2019-03-07T18:46:24+0000

Answer:

Explanation:

The congruence
$MN \cong PR$ is false, because they are not corresponding sides.

The corresponding sides are:

$MN \cong PQ\\NO \cong QR\\MO \cong PR$

On the other hand, if
$\triangle ABC \cong \triangle PQR$ , then
$\angle Q \cong \angle B$ .

We know that
$m\angle Q=8v-6$ and
$m \angle B=3v+4$ , but they are equal, so

$8v-6=3v+4\\8v-3v=6+4\\5v=10\\v=2$

Then,

$m\angle Q=8v-6=8(2)-6=16-6=10\\m \angle B=3v+4=3(2)+4=6+4=10$

Therefore, those angles are equal to 10°.

In the second image, the given triangles have the following congruence:

$\angle DAB \cong \angle CAB\\\angle DBA \cong \angle CBA$

Also, they have side AB in common.

Therefore,
$\triangle ABC \cong \triangle ABD$ , by ASA.