Question

Given the equation below:

What is the value of p if p is positive?

Answer 1

`√(3p^2+6)-9=0\implies √(3p^2+6)=9\implies \stackrel{\textit{squaring both sides}}{(√(3p^2+6))^2=9^2} \\\\\\ √((3p^2+6)^2)=81\implies 3p^2+6=81\implies 3p^2=75 \\\\\\ p^2=\cfrac{75}{3}\implies p^2=25\implies p=\pm√(25)\implies p=\pm 5\implies \stackrel{positive}{p=5}`