How do I solve this problem

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asked Jan 23, 2019 160k views

1 Answer

Wjin · Answer 1 · 2019-01-29T05:51:18+0000

Answer:
sqrt 100 < sqrt 110 < sqrt 121

the square root of 100 as a perfect square is 10
the square root of 121 as a perfect square is 11

The square root in the middle is in between the perfect squares of 10^2 and 11^2.

How do I solve this problem

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